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f(x)=("ln"(x^(2)+e^(x)))/("ln"(x^(4)+e^(...

`f(x)=("ln"(x^(2)+e^(x)))/("ln"(x^(4)+e^(2x)))." Then "underset(xtooo)limf(x)" is equal to "`

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The correct Answer is:
1.414
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