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For the equation 3x^2+p x+3=0,p >0, if o...

For the equation `3x^2+p x+3=0,p >0,` if one of the root is square of the other, then `p` is equal to `1/3` (b) 1 (c) 3 (d) `2/3`

A

`1//3`

B

1

C

3

D

`2//3`

Text Solution

Verified by Experts

The correct Answer is:
C
Let `alpha, alpha^(2)` be the roots of `3x^(2)+px+3=0`
Now, `S=alpha+alpha^(2)=-p//3,P=alpha^(3)=1`
`implies alpha-1, omega, omega^(2)`
Now, `alpha+alpha^(2)=-p//3`
`implies omega+omega^(2)=-p//3`
`implies -1=-p//3`
`impliesp=3`
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