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If a, b, d and p are distinct non - zero...

If a, b, d and p are distinct non - zero real numbers such that `(a^2+b^2 + c^2) p^2 - 2(ab+bc+cd)p+(b^2 + c^2 +d^2) le 0` then n. Prove that a, b, c, d are in G. P and ad = bc

A

are in AP

B

are in GP

C

are in HP

D

satisfy `ab = cd`

Text Solution

Verified by Experts

The correct Answer is:
B

Here, `(a^(2) + b^(2) + c^(2)) p^(2) -2 (ab + bc + cd) p + (b^(2) + c^(2) + d^(2)) le 0`
`rArr (a^(2) p^(2) - 2abp + b^(2)) + (b^(2) p^(2) -2bcp + c^(2)) + (c^(2) p^(2) -2cdp + d^(2)) le 0`
`rArr (ap - b)^(2) + (bp -c)^(2) + (cp -d)^(2) le 0`
[since, sum of squares is never less than zero]
Since, each of the squares is zero.
`:. (ap = b)^(2) = (bp -c)^(2) + (cp -d)^(2) = 0`
`rArr p = (b)/(a) = (c)/(b) = (d)/(c)`
`:.` a, b, c, d are in GP.
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