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Let,a1,a2a,a3,…. be in harmonic progress...

Let,`a_1,a_2_a,a_3,….` be in harmonic progression with `a_1=5 " and " a_(20)=25` The least positive integer n for which `a_n lt 0 `

A

22

B

23

C

24

D

25

Text Solution

Verified by Experts

The correct Answer is:
D

Plan nth term of HP, `t_(n) = (1)/(a + (n-1)n)`
Here, `a_(1) = 5, a_(20) = 25` for HP
`:. (1)/(a) = 5 and (1)/(a + 19d) = 25`
`rArr (1)/(5) + 19d = (1)/(25) rArr 19d = (1)/(25) - (1)/(5) = -(4)/(25)`
`:. d = (-4)/(19xx25)`
Since, `a_(n) lt 0`
`rArr (1)/(5) + (n-1) d lt 0`
`rArr (1)/(5) - (4)/(19xx25) (n-1) lt 0 rArr (n-1) gt (95)/(4)`
`rArr n gt 1 + (95)/(4) or n gt 24.75`
`:.` Least positive value of `n = 25`
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