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Let a1,a2,a3…., a49 be in A.P . Such th...

Let `a_1,a_2,a_3…., a_49` be in A.P . Such that `underset(k=0)overset(12)Sigma a_(4k+1)=416` and `a_9+a_(43)=66` .If `a_1^2+a_2^2 +…+ a_(17)` = 140 m then m is equal to

A

66

B

68

C

34

D

33

Text Solution

Verified by Experts

The correct Answer is:
C

We have, `a_(1), a_(2), a_(3),...a_(49)` are in AP
`underset(k=1)overset(12)sum a_(4k +1) = 416 and a_(9) + a_(43) = 66`
Let `a_(1) = a and d` = common difference
`:' a_(1) + a_(5) + a_(9) + ...+ a_(49) = 416`
`:. a + (a + 4d) + (a + 8d) + ...+ (a + 48d) = 416`
`rArr (13)/(2) (2a + 48d) = 416`
`rArr a + 24d = 32`...(i)
Also `a_(9) + a_(43) = 66`
`:. a + 8d + a + 42d = 66`
`rArr 2a + 50d + 66`
`rArr a + 25d = 33`...(ii)
solving Eqs. (i) and (ii), we get
`a = 8 and d =1`
Now, `a_(1)^(2) + a_(2)^(2) + a_(3)^(2) + ...+ a_(17)^(2) = 140m`
`8x^(2) + 9^(2) + 10^(2) + ...+ 24^(2) = 140 m`
`rArr (1^(2) + 2^(2) + 3^(2) + ...+ 24^(2)) - (1^(2) + 2^(2) + 3^(2) + ...+ 7^(2)) = 140 m`
`rArr (24 xx 25 xx 49)/(6) - (7xx 8 xx 15)/(6) = 140 m`
`rArr (3xx 7 xx 8 xx 5)/(6) (7 xx 5 -1) = 140 m`
`rArr 7 xx4 xx 5 xx 34 = 140 m`
`rArr 140 xx 34 = 140 m rArr m = 34`
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