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If f(x) = sin−1 (2x/1+x^2θ), then f' (√3...

If f(x) = sin−1 (2x/1+x^2θ), then f' (√3) is

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The correct Answer is:
D
Given, `f(x)=|x-1|`
` therefore f(x^(2))=|x^(2)-1|`
`and {f(x)}^(2)=(x-1)^(2)`
`rArr f(x^(2)) ne (f(x))^(2)`, hence (a) is false.
Also, `f(x+y)=|x+y-1|`
` and f(x)=|x-1|`,
`f(y)=|y-1|`
`rArr f(x+y) ne f(x) +f(y),` hence (b) is false.
`f(|x|)=||x|-1|`
` and |f(x) |=||x-1||=|x-1|`
` therefore f(|x|) ne |f(x)|,` hence (c) is false.
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