Home
Class 12
MATHS
If the Boolean expression (po+q)^^(~ps...

If the Boolean expression
`(po+q)^^(~psquareq)` is equivalent to `p^^q` where `o+, square epsilon{^^,vv}` then the ordered pair `(o+, square)` is

A

`(wedge,vee)`

B

`(wedge,wedge)`

C

`(wedge, vee)`

D

`(vee, vee)`

Text Solution

Verified by Experts

The correct Answer is:
A

Let us check all the options
(A) Consider, `o+ =wedge and *=vee.`
In that case, we get
Promotional Banner

Similar Questions

Explore conceptually related problems

The Boolean Expression (p^^~ q)vvqvv(~ p^^q) is equivalent to :

The boolean expression ~ (p rArr (~ q)) is equivalent to

~(pvvq)vv(~p^^q) is equivalent to

If the Boolean expression (p oplusq)wedge (~p Theta q) is equivalent to p wedge q , where oplus, Theta in {vee, wedge} , then the ordered pair (oplus, Theta) is

The expression ~(~p to q) is logically equivalent to

The Boolean expression ((p wedge q) vee (p vee ~q)) wedge (~p wedge ~q) is equivalent

lf r, s, t are prime numbers and p, q are the positive integers such that their LCM of p,q is r^2 t^4 s^2, then the numbers of ordered pair of (p, q) is (A) 252 (B) 254 (C) 225 (D) 224

For any two statements p and q, ~(pvvq)vv(~p^^q) is logically equivalents to

If the sum of the coefficients in the expansion of (q+r)^(20)(1+(p-2)x)^(20) is equal to square of the sum of the coefficients in the expansion of [2rqx-(r+q)*y]^(10) , where p , r , q are positive constants, then