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The variance of first 50 even natural nu...

The variance of first 50 even natural numbers is

A

`(833)/(4)`

B

833

C

437

D

`(437)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
Here, `bar(X) = (sumX_(i))/(n)=(2+4+6+8+ ... +100)/(50)=(50xx51)/(50)=51`
` " "[ because sum2n=n(n+1), " here " n=50]`
Variance, ` sigma^(2)=(1)/(n) sumX_(i)^(2)-(bar(X))^(2)`
`=(1)/(50) (2^(2)+4^(2)+ ... +100^(2))-(51)^(2)=833`
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