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If in triangle ABC, a = (1 + sqrt3) cm, ...

If in triangle `ABC, a = (1 + sqrt3) cm, b = 2 cm, and angle C = 6` then find the other two angles and the third side

Text Solution

Verified by Experts

The correct Answer is:
`c = sqrt(6), angleA = 45^(@)` and `angleA = 45^(@)`

Given that ,
`a=1+sqrt(3)b=2 and angle C=60^(@)`
We have, `c^(2)=a^(2)+b^(2)-2ab cos C`
`rArr c^(2)=(1+sqrt(3))^(2)+4-2(1+sqrt(3))*2 cos 60^(@)`
`rArr c^(2)=1+2sqrt(3)+3+4-2-2sqrt(3)`
`rArr c^(2)-6`
`rArr c= sqrt(6)`
Using sin rule,
`(a)/(sinA)=(b)/(sinB)=(c)/(sinC)`
`rArr (1+sqrt(3))/(sinA)=(2)/(sinB)=(sqrt(6))/(sin 60^(@))`
`:. sin B=(2 sin 60^(@))/(sqrt(6))=(2xx(sqrt(3))/(2))/(sqrt(6))=(1)/(sqrt(2))`
`rArr =B=45^(@)`
` :. A=180^(@)-(60^(@)+45^(@))=75^(@)`
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