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If x^2+y^2=1then...

If `x^2+y^2=1`then

A

`yy''-2(y')^(2)+1=0`

B

`yy''+(y')^(2) + 1=0`

C

`yy''+(y')^(2) - 1 = 0`

D

` yy''+2(y')^(2) + 1 = 0 `

Text Solution

Verified by Experts

The correct Answer is:
B
Given, ` x^(2) + y^(2) = 1`
On differentiating w.r.t. we get
` 2x+2yy'= 0 `
` rArr" " x+ yy' = 0`.
Again, differentiating w.r.t. x, we get
` 1+y'y'+yy'' = 0`
` rArr" " 1+(y')^(2) + yy'' = 0`
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