The number of divisors of the form (4n+2...

The number of divisors of the form `(4n+2)` of the integer 240 is

A

4

B

8

C

10

D

3

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The correct Answer is:

A

Since , `240 = 2^(4) .3.5`
`therefore` Total number of divisors `= (4 + 1)(2)(2) = 20`
Out of these 2, 6, 10, and 30 are of the form 4n + 2.

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