about to only mathematics

Options

A. `cos beta gt 0`
B. ` sin beta lt 0`
C. ` cos ( alpha + beta) gt 0`
D. ` cos alpha lt 0`

Answer

B, C, D

Explanation

Here, `alpha = 3sin ^(-1) ((6)/(11)) and beta = 3 cos ^(-1) ((4)/(9)) "as " (6)/(11) gt (1)/(2)`
`rArr sin^(-1)((6)/(11)) gt sin ^(-1)((1)/(2)) = (pi)/(6)`
`therefore " " alpha = 3 sin ^(-1) ((6)/(11)) gt (pi)/(2)`
`rArr " " cos alpha lt 0`
Now, `" " beta = 3 cos ^(-1)((4)/(9))`
As ` " " (4)/(9) lt (1)/(2) rArr cos ^(-1) ((4)/(9)) gt cos ^(-1) ((1)/(2)) = (pi)/(3)`
`therefore " " beta = 3 cos ^(-1) ((4)/(9)) gt pi`
`therefore cos beta lt 0 and sin beta lt 0`
Now, `alpha + beta ` is slightly greater that ` ( 3pi )/(2)`.
`therefore " " cos ( alpha + beta ) gt 0`