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Let O be the origin and let PQR be an a...

Let O be the origin and let PQR be an arbitrary triangle the point S is such that
`vec(OP) . vec(OQ) + vec(OR).vec(OS)= vec(OR) -vec(OP)+vec(OQ).vec(OS).`
`=vec(OQ). vec(OR).vec(OP).vec(OS)`then the trianle PQR has S has S as its

A

centroid

B

orthocentre

C

incentre

D

circumcentre

Text Solution

Verified by Experts

The correct Answer is:
B
OP .OQ +OR . OS =OR .OP + OQ. OS
`rArr OP (OQ- OR) +OS (OR -OQ) =0`
`rArr (OP-OS) (OQ- OR) =0`
`rArr SP. RQ =0`
Similarly SR. PQ= 0 and SQ . PR =0
`:. `S is orthocentre .
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