Home
Class 12
MATHS
Consider the planes 3x-6y-2z=15a n d2x+y...

Consider the planes `3x-6y-2z=15a n d2x+y-2z=5.` Statement 1:The parametric equations of the line intersection of the given planes are `x=3+14 t ,y=2t ,z=15 tdot` Statement 2: The vector `14 hat i+2 hat j+15 hat k` is parallel to the line of intersection of the given planes.

A

Statement I is true, Statement II is also true,
Statement II is the correct explanation of
Statement I

B

Statement I is true, Statement II is also true,
Statement II is not the correct explanation of
Statement I

C

Statement I is true, Statement II is false

D

Statement I is false, Statement II is true

Text Solution

Verified by Experts

The correct Answer is:
D

Given planes are `3x-6y-2z=15` and `2x+y-2z=5.`
For z=0, we get x=3, y=-1
Since, direction ratios of planes are
`lt3,-6,-2gt" and "lt2,1,-2gt`
Then the DR's of line of intersection of planes is `lt14,2,15gt` and line is
`(x-3)/(14)=(y+1)/(2)=(z-0)/(15)=lambda" "["say"]`
`implies" "s=14lambda+3,y=2lambda-1,z=15lambda`
Hence, Statement I is false.
But Statement II is true.
Promotional Banner

Similar Questions

Explore conceptually related problems

Consider the planes 3x-6y-2z-15 =0 and 2x+y-2z - 5=0 Statement 1:The parametric equations of the line intersection of the given planes are x=3+14 t ,y=2t ,z=15 tdot Statement 2: The vector 14 hat i+2 hat j+15 hat k is parallel to the line of intersection of the given planes.

Consider the planes 3x-4y+5z=10 and 2x+2y-3z=4 i.Write the equation of the plane through the line of intersection of the above planes. ii. Write the direction ratios of the line x=2y=3z iii. If the line in (ii) is parallel to the plane in (i), show that the plane is x-20y+27z=14.

Show that the line of intersection of the planes vec rdot( hat i+2 hat j+3 hat k)=0a n d vec r=(3 hat i+2 hat j+ hat k)=0 is equally inclined to ia n dkdot Also find the angle it makes with jdot

Reduce the equation of line x-y+2z=5a d n3x+y+z=6 in symmetrical form. Or Find the line of intersection of planes x-y+2z=5a n d3x+y+z=6.

Find the vector equation of the line passing through (1,2,3) and parallel to the planes vec rdot( hat i- hat j+2 hat k)a n d vec rdot(3 hat i+ hat j+ hat k)=6.

The equation of the plane through the point whose position vecot ris 2hat I - hat j + hatk and perpendicular to the vector is 4hati + 2hatj - 3 hat k is 4x+2y-3z = k then k is :

Find the vector equation of the line passing through (1, 2, 3 ) and parallel to the planes -> rdot( hat i- hat j+2 hat k)=5\ a n d\ -> rdot(3 hat i+ hat j+ hat k)=6.

Equation of line of projection of the line 3x-y+2z-1=0=x+2y-z=2 on the plane 3x+2y+z=0 is

The intersection of the planes 2 x-y-3 z=8 and x+2 y-4 z=14 is the line L . The value of a ' for which the line L is perpendicular to the line through (a, 2,2) and (6,11,-1 is