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The general solution of the trigonometri...

The general solution of the trigonometric equation `sinx+cosx=1` is given by 1.x=2npi,n=0,+-1,+-2`.. 2. x=2npi+pi/2; n=0,+-1,+-2, dot` 3. x='npi'+(-1)^n (pi/4)-(pi/4) ,n=0,+-1,+-2, ` 4.`none of these`

A

`x=2npi,n = 0, pm1, pm2`…..

B

`x= 2npi + pi//2, n = 0,pm1,pm 2`……

C

`x= npi+(-1)^(n)(pi)/(4).(pi)/(4),n = 0,pm 1,pm 2`……

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
C

Given `sin x + cos x = 1`
On dividing and multiplying each terms by `sqrt(2)`, we get
`(1)/(sqrt(2)) sin x +(1)/(sqrt(2)) cos x = (1)/(sqrt(2))`
`rArr sin x cos.(pi)/(4) = cos x sin .(pi)/(4) = (1)/(sqrt(2))`
`rArr sin (x+(pi)/(4)) = sin((pi)/(4))`
`rArr x + (pi)/(4) = npi + (-1)^(n) (pi)/(4)`
`rArr x = npi+(-1)^(n) (pi)/(4)-(pi)/(4), n in I`
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