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If z = (1)/(1 - cos theta - i sin theta...

If z = `(1)/(1 - cos theta - i sin theta),` the Re (z)=

Text Solution

Verified by Experts

The correct Answer is:
`A + iB = (1)/(2(1 + 3 cos^(2) (theta)/(2))) -I (cot (theta//2))/(1 + 3 cos^(2) (theta//2))`
Now `(1)/((1-cos theta)+2i sin theta)=(1)/(2 sin^2 ""theta/2+4i sin""theta/2 cos""theta/2)`
`=1/(2sin""theta/2(sin^2""theta/2+4 cos ^2""theta/2))xx(sin""theta/2-2 i cos ""theta/2)/((sin""theta/2-2 icos ""theta/2))`
`=(sin""theta/2-2i cos""theta/2)/(2 sin""theta/2(1 +3 cos^2""theta/2))`
`rArr A + iB =(1)/(2(1+3 cos^2""theta/2))-i(cot""theta/2)/(1+3 cos^2 ""theta/2)`
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