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Three of six vertices of a regular hexag...

Three of six vertices of a regular hexagon are chosen at random. The probability that the triangle with three vertices is equilateral is `1//2` b. `1//5` c. `1//10` d. `1//20`

A

`1//2`

B

`1//5`

C

`1//10`

D

`1//20`

Text Solution

Verified by Experts

The correct Answer is:
C
Three vertices out of 6 can be chosen in `""^(6)C_3=20`
Only two equilateral
triangle can be formed
`Delta AEC " and " Delata BFD`
`therefore` Favourable ways =2
So, required probability
`=2/20 =1/10`
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