Three faces of a fair dice are yellow, two are red and one is blue. Find the probability that the dice shows (a) yellow, (b) red and (c ) blue face.

Answer

A, C

Explanation

According to given condition,
P ( yellow at the first toss) `=3/6=1/2`
P (red at the second toss) `=2/6=1/3 `
and P (blue at the third toss) `=1/6`
Therefore, the probability of the required event `=1/2xx1/3xx1/6=1/36`