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An unbiased die with faced marked 1, 2, ...

An unbiased die with faced marked 1, 2, 3, 4, 5, and 6 is rolled four times. Out of four face value obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than five is then `16//81` b. `1//81` c. `80//81` d. `65//81`

A

`16//81`

B

`1//81`

C

`80//81`

D

`65//81`

Text Solution

Verified by Experts

The correct Answer is:
A
Let A=getting not less than 2 and not greater than 5
`implies A={2,3,4,5} implies P(A) =(4)/( 6)`
But die is rolled four times , therefore the probability in getting four throws
`((4)/(6))((4)/(6))((4)/(6))((4)/(6))=(16)/(81)`
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