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The circle passing through (1,-2) and ...

The circle passing through (1,-2) and touching the axis of x at (3,0) passing through the point

A

(-5, 2)

B

(2, -5)

C

(5, -2)

D

(-2, 5)

Text Solution

Verified by Experts

The correct Answer is:
C
Let the equation of circle be
`(x-3)^(2)+(y-0)^(@)+lambday=0`
` (##41Y_SP_MATH_C16_E04_005_S01.png" width="80%">
As it passes through (1, -2)
`therefore" " (1-3)^(2)+(-2)^(2)+lambda(-2)=0`
`rArr " " 4+4-2lambda=0rArrlambda=4`
`therefore` Equation of circle is
`(x-3)^(2)+y^(2)+4y=0`
by hit and trial method, we are that point (5, -2) satisfies equation of circle.
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