Home
Class 12
MATHS
There si a parabola having axis as x-axi...

There si a parabola having axis as `x`-axis, vertex is at a distance of `2` unit from origin & focus is at `(4,0)`. Which of the following point does not lie on the parabola. (a) `(6,8)` (b) `(5,2sqrt(6))` (c) `(8,4sqrt(3))` (d) `(4,-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

According to given information, we have the following figure.

Now, if the origin is shifted to (2,0) and (X,Y) are the coordinates with respect to new origin, then equation of parabola is `Y^(2) = 4aX`,
where, `X = x - 2` and `Y = y` and `a = 4 - 2 = 2`
`:. y^(2) = 8(x - 2)`
Note that (8,6) is the only point which does not satisfy the equation.
Promotional Banner

Similar Questions

Explore conceptually related problems

If the vertices of the parabola be at (-2,0) and (2,0) and one of the foci be at (-3,0) then which one of the following points does not lie on the hyperbola? (a) (-6, 2sqrt(10)) (b) (2sqrt6,5) (c) (4, sqrt(15)) (d) (6, 5sqrt2)

Axis of the parabola x^2 - 3y - 6x + 6 = 0 is

The vertex of the parabola y^2 + 4x = 0 is

A parabola is drawn touching the axis of x at the origin and having its vertex at a given distance k form this axis Prove that the axis of the parabola is a tangent to the parabola x^2=-8k (y-2k) .

Let the length of latus rectum of an ellipse with its major axis along x-axis and center at the origin, be 8. If the distance between the foci of this ellipse is equal to the length of the minor axis , then which of the following points lies on it: (a) (4sqrt2, 2sqrt2) (b) (4sqrt3, 2sqrt2) (c) (4sqrt3, 2sqrt3) (d) (4sqrt2, 2sqrt3)

The length of the chord of the parabola y^2=x which is bisected at the point (2, 1) is (a) 2sqrt(3) (b) 4sqrt(3) (c) 3sqrt(2) (d) 2sqrt(5)

The axis of the parabola x^(2)=-4y is ……. .

Radius of the circle that passes through the origin and touches the parabola y^2=4a x at the point (a ,2a) is (a) 5/(sqrt(2))a (b) 2sqrt(2)a (c) sqrt(5/2)a (d) 3/(sqrt(2))a

The largest value of a for which the circle x^2+y^2=a^2 falls totally in the interior of the parabola y^2=4(x+4) is (a) 4sqrt(3) (b) 4 (c) 4(sqrt(6))/7 (d) 2sqrt(3)

A is a point on either of two lines y+sqrt(3)|x|=2 at a distance of 4/sqrt(3) units from their point of intersection. The coordinates of the foot of perpendicular from A on the bisector of the angle between them are (a) (-2/(sqrt(3)),2) (b) (0,0) (c) (2/(sqrt(3)),2) (d) (0,4)