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Find the equation of the normal to the c...

Find the equation of the normal to the curve `x^(2)` = 4y which passes through the point (1, 2).

Text Solution

Verified by Experts

The correct Answer is:
x + y = 3
Equation of normal to `x^(2) = 4y` is `x = my - 2m - m^(3)`
and passing through (1,2)
`:. 1 - 2 m - 2m - m^(3)`
`implies m^(3) = - 1` or m = -1
Thus, the required equation of normal is
x = - y + 2 + 1 or x + y = 3 is required equation.
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