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Differentiate: (logx)^x+x^(logx) with re...

Differentiate: `(logx)^x+x^(logx)` with respect to `xdot`

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To differentiate the expression \( ( \log x )^x + x^{\log x} \) with respect to \( x \), we will follow a systematic approach. Let's denote: \[ y = (\log x)^x + x^{\log x} \] ### Step 1: Differentiate the first term \( u = (\log x)^x \) ...
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