A sample of calcuium carbonate `(CaCO_(3))` has the following percentage composition: `Ca=40%, C=12%, O=48%` If the law of constant proportions is true. Then the weight of calcium in `4 g` of a sample of calcium carbonate obtained from another source will be

A substance on analysis gave the following percentage composition Na = 43.4% C = 11.3% O = 45.3% Calculate the empirical formula.

An organic compound has the following percentage composition : C= 48%, H= 8% N= 28% and rest of oxygen. Calculate the empirical formula of the compound.

What is the simplest formula of the compound which has the following percentage composition carbon 80% , hydrogen 20% , if the molecular mass is 30. calculate its molecular formula ?

Chalk contains calcium, carbon and oxygen in the ratio 10:3:12. Find the percentage of carbon in chalk.

An organic substance containing carbon, hydrogen and oxygen gave following percentages, C= 40.68%, H_(2) = 5.085% and O_(2) = 54.22%. The vapour density of the compound is 59. Calculate the molecular formula of the compound.

The air is a mixture of number of gases. The major components are oxygen and nitrogen with approximate proportion of 20% is to 79% by volume at 298K. The water is in equilibrium with air at a pressure of 10 atm. Henry's law constants for oxygen and nitrogen at 298 K are 3.30xx10^7mm and 6.51xx10^7mm respectively. calculate the composition of these gases in water.

0.246 g of an organic compound gave 0.198 g of CO_2 and 0.101 g of H_2O on complete combustion calculate the percentage composition of Carbon and Hydrogen.