`6 xx 10^(-3)` mole `K_2 Cr_2 O_7` reacts completely with `9 xx 10^(-3)` mole `X^(n+)` to given `XO_3^- and Cr_^(3+)`. The value of `n` is :

6xx10^(-3) mole K_(2)Cr_(2) C_(7) reacts completely with 9xx10^(-3) mole X^(n+) to give XO_(3)^(-) and Cr^(3+) . The value of n is :

What happens when K_2Cr_2O_7 reacts with acidified FeSO_4 ?

Simplify: (–2)^3 xx (–10)^3

A solution contaning 2.7 xx 10^(-3) mol of A^(2+) "ion required" 1.6 xx 10^(-3)mol of MnO_(4)^(2-) for the oxidation of A^(2+) "to" AO_(3)^(-) the medium is:

How acidified K_2Cr_2O_7 reacts with the following : FeSO_4

How acidified K_2Cr_2O_7 reacts with the following : Na_2SO_4

Complete the following reaction equation : S_2O_3^(2-)+ Cr_2O_7^(2-)+ H^(+) rarr

Calculate number of neutrons present in 12 xx 10^25 atoms of oxygen (8O^17) : (Given : N_A=6 xx 10^23 )