KMnO4 reacts with oxalic acid according ...

`KMnO_4` reacts with oxalic acid according to the equation `2MnO_4 + 5C_2 O_4^(2-) + 16H^+ rarr 2Mn^(2+) + 10CO_2 + 8H_2O` Here, `20mL` of `0.1M KHMnO_4` is equivalent to :

A

(a) `20 mL of 0.5M H_(2)C_(2)O_(4)`

B

(b) `50 mL of 0.1 M H_(2)C_(2)O_(4)`

C

(c) `50 mL of 0.5M H_(2)C_(2)O_(4)`

D

(d) `20 mL of 0.1M H_(2)C_(2)O_(4)`

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