The `NH_3` evolved due to complete conversion of `N` from `1.12g` sample of protien was absorbed in `45mL` of `0.4 NHNO_3`. The excess acid required `20mL` of `0.1NNaOH`. The % N in the sample is :

0.80g is impure (NH_4)SO_4) was boiled with 100mL of 0.2N NaOH solution till all the NH_3 (g) evolved. The remaining solution was diluted to 250mL. 25mL of this solution was neutralized using 5mL of 0.2 NH_2 SO_4 solution. The percentage purity of the (NH_4)_2SO_4 sample is :

When 2.5g of a sample of mohr's salt reacts completely with 50mL of N/10 KMnO_4 solution. The % purity of the sample of Mohr's salt is :

320mg of sample of magnesium having a coating of its oxide required 20mL of 0.1M hydrochloric acid for the complete neutralisation of the latter. The composition of the sample is :

Oleum is considered as a solution of SO_(3) in H_(2)SO_(4) , which is obtained by passing SO_(3) in solution of H_(2)SO_(4) When 100 g sample of oleum is diluted with desired mass of H_(2)O then the total mass of H_(2)SO_(4) obtained after dilution is known is known as % labelling in oleum. For example, a oleum bottle labelled as ' 019% H_(2)SO_(4) ' means the 109 g total mass of pure H_(2)SO_(4) will be formed when 100 g of oleum is diluted by 9 g of H_(2)O which combines with all the free SO_(3) present in oleum to form H_(2)SO_(4) as SO_(3)+H_(2)O to H_(2)SO_(4) 1 g of oleum sample is diluted with water. The solution required 54 mL of 0.4 N NaOH for complete neutralization. The % free SO_(3) in the sample is :

0.45g of an acid of mol. Mass 90 was neutralised by 20mL of 0.5 N caustic potash (KOH) . The basicity of acid is :

Find out % of oxalate ion in a given sample of an alkali metal oxalate salt, 0.30g of it is dissolved in 100mL water and its required 90mL of centimolar KMnO_4 solution in acidic medium :

A sample containing HAsO_2 (mol. mass =180 ) and weighing 3.78g is dissolved and diluted to 250mL in a volumetric flask. A 50mL sample (aliquat) is withdrawn with a pipet and titrated with 35mL of 0.05 M solution of I_2 . Calculate the percentage HAsO_2 in the sample :

A mixture of H_(2)SO_(4) and H_(2)C_(2)O_(4) (oxalic acid ) and some inert impurity weighing 3.185 g was dessolved in water and the solution made up to 1litre. 10 mL of this solution required 3 mL of 0.1 N NaOH for complete neutralization. In another experiment 100 mL of the same solution in hot condition required 4 mL of 0.02 M KMnO_(4) solution for complete reaction. The mass % of H_(2)SO_(4) in the mixture was:

If 20 mL of 0.1 M NaOH is added to 30 mL of 0.2 M CH_(3)COOH (pK_(a)=4.74), the pH of the resulting solution is :

5 g sample contain only Na_(2)CO_(3) and Na_(2)SO_(4) . This sample is dissolved and the volume made up to 250 mL. 25 mL of this solution neutralizes 20 mL of 0.1 M H_(2)SO_(4) . Calcalute the % of Na_(2)SO_(4) in the sample .