250ml of a 1.5M solution of sulphuric acid is diluted by adding 5L of water. what is the molarity of the diluted solution?

4L of 0.02 M aqueous solution of NaCI was diluted by adding one litre of water. The molality of the resultant solution is ________

The mole fraction of water in sulphuric acid solution is 0.85. Calculate the molality of the solution.

4L of water is added to 2L of 6M HCl solution. What is the molarity of resulting solution .

A solution of glucose in water is labelled as 10 percent w/w . What would be the molality and mole fraction of each component in the solution? If the density of the solution is 1.2g mL^-1 , then what shall be the molarity of the solution?

Commercially available sample of sulphuric acid is 15% H_2SO_4 by weight (density=1.10g mL^-1 ) . Calculate the molarity of the solution.

Why conc. sulphuric acid is always diluted by adding sulphuric acid to water with constant stirring and not water to the acid ?

In an experiment to estimate the size of a molecule of oleic acid 1mL of oleic acid is dissolved in 19 mL of alochol. Then 1 mL of this solution is diluted to 20 mL by adding alcohol. Now 1 drop of this diluted solution is placed on water in a shallow trough. The solution spreads over the surface of water forming one molecule thick layer. Now, lycopodium powder is sprinkled evenly over the film and its diameter is measured. Knowing the volume of the drop and area of the film we can calculate the thickness of the film which will give us the size of oleic acid molecule. Read the passage carefully and answer the following questions : What will be the volume of oleic acid in one drop of this solution?

In an experiment to estimate the size of a molecule of oleic acid 1mL of oleic acid is dissolved in 19 mL of alcohol. Then 1 mL of this solution is diluted to 20 mL by adding alcohol. Now 1 drop of this diluted solution is placed on water in a shallow trough. The solution spreads over the surface of water forming one molecule thick layer. Now, lycopodium powder is sprinkled evenly over the film and its diameter is measured. Knowing the volume of the drop and area fo the film we can calculate the thickness of the film which will give us the size of oleic acid molecule. Read the passage carefully and answer the following questions : What is the role of lycopodium powder?

In an experiment to estimate the size of a molecule of oleic acid 1mL of oleic acid is dissolved in 19 mL of alcohol. Then 1 mL of this solution is diluted to 20 mL by adding alcohol. Now 1 drop of this diluted solution is placed on water in a shallow trough. The solution spreads over the surface of water forming one molecule thick layer. Now, lycopodium powder is sprinkled evenly over the film and its diameter is measured. Knowing the volume of the drop and area of the film we can calculate the thickness of the film which will give us the size of oleic acid molecule. Read the passage carefully and answer the following questions : why do we dissolve oleic acid in alcohol ?

A sample of NaOH weighing 0.38 g is dissolved in water and solution is made to 50.0 mL in a volumetric flask. What is the molarity of the solution?