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A(2)+B(2)to2AB, R.O.R.=k[A(2)]^(a)[B(2)]...

`A_(2)+B_(2)to2AB`, R.O.R.=`k[A_(2)]^(a)[B_(2)]^(b)`
`{:(,"Initial"[A_(2)],"Initial"[B_(2)],R.O.R.(r) Ms^(-1)),(,0.2,0.2,0.04),(,0.1,0.4,0.04),(,0.2,0.4,0.08):}`
Order of reaction with respect to `A_( 2)` and `B_(2)` are respectively :

A

a=1,b=1

B

a=2,b=0

C

a=2,b=1

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
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