For reaction A `rarr` B , the rate constant `K_(1)=A_(1)(e^(-E_(a_(1))//RT))` and the reaction `X rarr Y` , the rate constant `K_(2)=A_(2)(e^(-E_(a_(2))//RT))` . If `A_(1)=10^(9)`, `A_(2)=10^(10)` and `E_(a_(1))`=1200 cal/mol and `E_(a_(2))` =1800 cal/mol , then the temperature at which `K_(1)=K_(2)` is : (Given , R=2 cal/K-mol)
a) `300K`
b) `300 xx 2.303 K`
c) `(300)/(2.303 )K`
d) None of these

Options

A. 300K
B. `300 xx 2.303 K`
C. `(300)/(2.303 )K`
D. None of these

Answer

C