Size of nucleus was obtained by the equation `r=R_(0)A^(1//3)` , Where r is the radius of nucleus of mass no A. and `R_(0)` is a constant whose valie is equal to `1.5xx10^(-15)` metre.
(Given : 1 amu = `1.66xx10^(-24)g`)
What is the density of a nucleus of mass number A ?
a) `(4)/(3)pi(1.5xx10^(-15))^(3)` A
b) `1.17xx10^(17)kg//cm^(3)`
c) `1.17xx10^(17)kg//m^(3)`
d) none of these

Options

A. `(4)/(3)pi(1.5xx10^(-15))^(3)` A
B. `1.17xx10^(17)kg//cm^(3)`
C. `1.17xx10^(-17)kg//m^(3)`
D. none of these

Answer

B