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N(2)(g) reacts with H(2)(g) in either of...

`N_(2)`(g) reacts with `H_(2)`(g) in either of the following ways depending upon supply of `H_(2)`(g) :
`N_(2)(g)+H_(2)(g) to N_(2)H_(2)(l)`
`N_(2)(g)+2H_(2)(g) to N_(2)H_(4)`(g)
If 5 L `N_(2)`(g) and 3 L `H_(2)`(g) are taken initially (at same temperature and pressure ), calculate the contraction in valume after the reaction (in L ).

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