If `lamda_o and lamda` be the threshold wavelength and wavelength of incident light , the velocity of photoelectron ejected from the metal surface is :
What is the effect of decrease in wavelength of incident light on the velocity of photoelectrons?
The figure shows the stopping potential for the phototelectron versus (1/lambda) graph for two metals A and B, lambda being the wavelength of incident light How is the value of Planck's constant determined from the graph?
The figure shows the stopping potential for the phototelectron versus (1/lambda) graph for two metals A and B, lambda being the wavelength of incident light If the distance between the light source and the surface of metal A is increased, how will the stopping potentail for the electrons emitted from it be affected? justify your answer.
Work function of a metl surface is 4.2 eV. The maximum wavelength which can eject electrons from this metal surface is:
Calculate the threshold wavelength of photons, which can emit photoelectrons from cesium. Given that work function of cesium=1.8 eV.
Define the term work function of a metal. The threshold frequency of a metal is 2f_0 is incident on the metal plate, the maximum velocity of electrons emitted is v_1 , when the frequency of the incident radiation is increased of 5f_0 the maximum velocity of electrons emitted is v_2 . Find the ratio of v_1 to v_2 .
