An excited state of H atom emits a photon of wavelength `lamda` and returns in the ground state. The principal quantum number of excited state is given by:
A
`sqrt(lamdaR(lamdaR-1))`
B
`sqrt((lamdaR)/((lamdaR-1))`
C
`sqrt(lamdaR(lamdaR-1)`
D
`sqrt((lamdaR-1)/((lamdaR))`
Text Solution
Verified by Experts
Topper's Solved these Questions
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise Level- 1|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
Similar Questions
Explore conceptually related problems
In which atomic model electrons in the ground state are in stable equilibrium?
A set of atoms in an excited state decays
Estimate the ratio of the wavelength associated with the electron orbiting around the nucleus in the ground and first excited state of hydrogen atom.
Explain the meaning of ground state and excited state of an atom?
What is the order of speed of electrons in a hydrogen atom in ground state?
The electron in a hydrogen atom make a transtion n_(1) rarr n_(2) where n_(1) and n_(2) are the priocipal quantum number of the two states . Assume the Bohr model to be valid . The time period of the electron in the initial state is eight time that in the final state . The possible values of n_(1) and n_(2) are
The potential energy of an electron in the hydrogen atom is -6.8 eV. Indicate in which excited state, the electron is present?
