Home
Class 11
CHEMISTRY
de Broglie wavelength of an electron aft...

de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :

A

`lamda=(1.23)/sqrt(m)`

B

`lamda=(1.23)/sqrt(h)m`

C

`lamda=(1.23)/sqrt(V)nm`

D

`lamda=(1.23)/(V)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise Level- 1|1 Videos
  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos

Similar Questions

Explore conceptually related problems

What is de -Brogile wavelength of an eectron beam accelerated through a potential difference of 36 V?

What is the de-Broglie wavelength of an electron beam accelerated through a potential difference of 25 V?

Calculate the momentum and De Brogile wavelength of the electrons accelerated through a potential difference of 56V. Mass of electron is 9.1 xx 10^(-31) kg.

Calculate the momentum and de-Broglie wavelength of the electrons accelerated through a potential difference of 56V.

Derive the expression for de Broglie wavelength associated with an electron in a potential differences of V volts.