The equilibrium constant for a reaction is K, and the reaction quotient is Q . For a particular reaction mixture , the ration `(K)/(Q)` is 0.33. this means that:
A
the reaction mixture will equilirate to from more reactant species
B
the rection mixture will equilirate to from more product species
C
the equlibrium ratio of reactant to product concentration will be 3
D
the equilibrium ratio of reactant to product concentrations will be 0.33
Text Solution
Verified by Experts
The correct Answer is:
b
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
The rate constant of a reaction has same units as the rate of reaction. The reaction is of …..
What do you mean by Q value of a nuclear reaction?
If the rate constant for a first order reaction is k, the time (t) required for completion of 99 % of the reaction is given by
The activation energy for the reaction if k = A is
The rate law for a reaction is Rate = k[A]^(1//2)[B]^2 Can the reaction be an elementry reaction. Explain.
The rate of reaction is equal to rate constant of the reaction. What is the order of reaction?
The equilibrium constant for a reaction is 10. What will be the value of Delta G^(@) ? R = 8.314 jK^(-1) mol^(-1), T = 300K .
Equilibrium constant, K_(C ) for the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g) at 500 K is 0.061 At a particular time, the analysis shows that composition of the reaction mixture is 3.0 mol L^(-1)N_(2), 2.0 "mol L"^(-1) H_(2) , 0.5 mol L^(-1) NH_(3) . Is the reaction at equilibrium ? If not, in which direction does the reaction tends to proceed to reach equilibirum ?
Rate constant for a chemical reaction taking place at 500K is expressed as K=A. e^(-1000) The activation energy of the reaction is :