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Given [CS(2)]=0.120M,[H(2)]=0.10,[H(2)S]...

Given `[CS_(2)]=0.120M,[H_(2)]=0.10,[H_(2)S]=0.20 and [CH_(4)]=7.40xx10^(-5)M ` for the following reaction at `900^(@)`C at eq.Calculate the equilibrium constant `(K_(c))`.
`CS_(2)(g) +4H_(2)(g)->CH_(4)+2H_(2)S(g)`

A

`0.0120`

B

`0.0980`

C

`0.280`

D

`0.120`

Text Solution

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The correct Answer is:
c
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