For the reaction `H_(2)(g)+CO(g)hArrCO(g)+H_(2)O(g),` if the initial concentration of`[H_(2)]=[CO_(2)]`and x moles /litres of hydrogen is consummed at equilibrium , the correct expression of `K_(p)` is :
A
`(x^(2))/((1-x)^(2))`
B
`((1-x)^(2))/((1-x)^(2))`
C
`(x^(2))/((2+x)^(2))`
D
`(x^(2))/((1-x)^(2))`
Text Solution
Verified by Experts
The correct Answer is:
a
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
For a reaction N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g))
For the reactions : C(s) + O_(2) (g) to CO_(2) (g)
For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with
For the reaction CO(g)+Cl_(2)(g)hArrCOCl_(2)(g) the value of (K_(c)/(K_(P))) is equal to :
For the reaction 2H(g)rarr H_(2)(g) , the sign of DeltaH and DeltaS respectively are :
The equilibrium constant K_(p) for the reaction H_(2)(g)+CO_(2)(g)hArrH_(2)(g)+CO(g) is 4.0 at 1660^(@)C Inittally 0.80 H_(2) and 0.80 mole CO_(2) are injecteed into a 5.0 litre flask what is the equilibrium concentraton of CO_(2)(g) ?
In the reaction, SO_2(g) + 2H_2S (g) rarr 2H_2O (l) + S (s) the reducing agents is
An equilibrium mixture of the reaction 2H_(2)S(g)hArr2H_(2)(g) + S_(2)(g) had 0.5 mole H_(2)S , 0.10 mole H_(2) and 0.4 mole S_(2) in one litre vessel. The value of equilibrium constants (K) in mole litre^(-1) is
At a certain temperature the equilibrium constant K_(c) is 0.25 for the reaction A_(2)(g)+B_(2)(g)hArrC_(2)(g)+D_(2)(g) If we take 1 mole of each of the four gases in a 10 litre container ,what would be equilibrium concentration of A_(2) (g)?
For the dissociation reaction N_(2)O_($) (g)hArr 2NO_(2)(g) , the degree of dissociation (alpha) interms of K_(p) and total equilibrium pressure P is: