Home
Class 11
CHEMISTRY
Heating a II group metal carbonate leads...

Heating a II group metal carbonate leads to decomposition as :
`BaCO_(3)(s)hArrBaO(s)+CO_(2)(g)`
Equilibrium will shift left

A

by addition of BaO (s)

B

by addition of `CO_(2)(g)`

C

by decreasing the temperature

D

by decreasing the volume of the vessel

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos
  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

Similar Questions

Explore conceptually related problems

Increase in the presssure for the following equilibrium results in the : H_(2)O(l)hArrH_(2)O(g) Equilibrium will shift left

For the reactions : C(s) + O_(2) (g) to CO_(2) (g)

Find out the value of K_(c) for each of the following equilibrium from the value of K_(p) : CaCO_(3)(s) hArr CaO(s) + CO_(2)(g), K_(p) = 167 atm at 1073 K.

When N_(2)O_(5) is heated at certain temperature, it dissociates as N_(2)O_(5)(g)hArrN_(2)O_(3)(g)+O_(2)(g),K_(c)=2.5 At the same time N_(2)O_(3) also decomposes as : N_(2)O_(3)(g)hArrN_(2)O(g)+O_(2)(g). "If initially" 4.0 moles of N_(2)O_(5) "are taken in" 1.0 litre flask and alowed to dissociate. Concentration of O_(2) at equilibrium is 2.5 M. "Equilibrium concentratio of " N_(2)O_(5) is :

Consider the reaction 2CO(g)+O_(2)(g)hArr2CO_(2)(g)+Heat Under what conditions shift is undetminable ?

Balance the following chemical equation: Pb(NO_3)_2(s) rarr 2PbO(s)+NO_2(g)+O_2(g)

Classify each of the following reactions 2KNO_3(s) rarr 2KNO_2(s)+O_2 (g)

Some inert gas is added at conastant volume to the following reaction at equilibrium N_(4)HS(s)hArrNH_(3)(g)+H_(2)s(g) ltbgt predict the effec of adding the inert gas:

Classify each of the following reactions 2KClO_3(s) gives 2KCL (s)+3O_2(g)

A definite amount of solid NH_(4)HS is placed in a flask already containing ammonia gas at a certain temperature and 0.1 atm pressure. NH_(4)HS decompses to give NH_(3) and H_(2)S and at equilibrium total pressure in flask is 1.1 atm. If the equilibrium constant K_(P) for the reaction NH_(4)HS(s) iff NH_(3)(g)+H_(2)S(g) is represented as zxx10^(-1) then find the value of z.