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The freezing point of a solution of 2.40...

The freezing point of a solution of 2.40 g of biphenyl(`C_(12)H_(10)`) in 75.0 g of benzene (`C_(6)H_(6)`) is `4.40^(@)C`. The normal freezing point of benzene is `5.50^(@)C`. What is the molal freezing point constant `(^(@)C//m)` for benzene ?

A

5.3

B

5.1

C

4.6

D

4.8

Text Solution

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The correct Answer is:
a
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