A solution containing 1.8 g of a compound (empirical formula `CH_(2)O`) in 40 g of water is observed to freeze at `-0.465^(@)`C. The molecules formulea of the compound is (`K_(f)` of water =1.86kg K`mol^(-1)`):
A
`C_(2)H_(4)O_(2)`
B
`C_(3)H_(6)`
C
`C_(4)H_(8)O_(4)`
D
`C_(6)H_(12)O_(6)`
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The correct Answer is:
d
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DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 1 (Q.62 To Q.91)|1 Videos
When 36.0 g of a solute having the empirical formula CH_(2)O is dissovled in 1.20 kg of water, the solution freezes at -0.93^(@)C . What is the moleculer formula of the solute ? ( K_(f) = 1.86^(@)C kg mol^(-1) )
15 g of an unknown molecular substance was dissolved in 450 g of water. The resulting solution freezes at - 0 . 34^(@) C . What is them molar ass of the substance ? ( K_(f) for water = 1. 86 K kg mol^(-1) )
A solution containing 12.5 g of a non- electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of the substance ( K_b for water = 0.52 K kg mol^(-) ).
18 g of a compound is dissolved in 10 kg of water so that the resulting solution freezes at - 8^(@) C . If K_(f) for water = 1 . 86 K/m . Calculate the molecular mass of the compound
35 g of compound is added in 1 kg of water so that the resulting solution freezes at - 10^(@) C . If K_(f) for water = 1. 86 K/m . Calculate the molecular mass of the compound
A solution of 1 . 25 g of non eletrolyute solute in 20 g of water freezes at 271 . 94 K. Calculate the molecular mass of solute. The molal depression constant for water is K_(f) = 1 . 86 K//m
The freezing point of solution containing 0.2 g of acetic acid in 20.0 g of benzene is lowered by 0.45^(@)C . Calculate the degree of association of acetic acid in benzene. (K_(f)=5.12 K^(@) mol^(-1) kg^(-1))
45g of ethylene glycol (C_2H_6O_2) is mixed with 600 g of water. Calculate: the freezing point of the solution. (K_f for water=1.86K kg mol^-1) .
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column
