A dilute solution contains 'x' moles of solute A in 1 kg of solvent with molal elevation constant `K_(b)`. The solute dimerises in the solution according to the following equation. The degree of association is (a) : `2A hArrA_(2)` The degree of assoicition is equal to :
a) `a = ((K_(b)x - /_\T_(b)))/(/_\T_(b)2)`
b) `a = (2(K_(b)x - /_\T_(b)))/(K_(b)x)`
c) `a =2 + (2/_\T_(b))/(K_(b)x)`
d) `a = (/_\T_(b))/(2K_(b)x)`
A
`a = ((K_(b)x - /_\T_(b)))/(/_\T_(b)2)`
B
`a = (2(K_(b)x - /_\T_(b)))/(K_(b)x)`
C
`a =2 + (2/_\T_(b))/(K_(b)x)`
D
`a = (/_\T_(b))/(2K_(b)x)`
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The correct Answer is:
b
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