One mole of an ideal gas undergoes a change of state (2.0) atm, 3.0 L) to (2.0 atm, 7.0 L) with a change in internal energy `(DeltaU) = 30` L-atm. The change in enthalpy `(DeltaH)` of the process in L-atm :

Options

A. 22
B. 38
C. 25
D. None of these

Answer

B

Explanation

At constant pressure, `DeltaH=DeltaU+P.DeltaV`
`=30 + 2xx4`
=38 atm-L