When two moles of an ideal gas `(C_(p.m.)=(5)/(2)R)` heated form 300K to 600K at constant pressure, the change in entropy of gas `(DeltaS)` is:

Options

A. `(3)/(2) R ln 2`
B. `-(3)/(2) R ln 2`
C. `5R ln 2`
D. `(5)/(2) R ln 2`

Answer

C

Explanation

`DeltaS=nC_(p,m)ln.(T_(2))/(T_(1))`
`=2xx(5)/(2)Rln.(600)/(300)`
`=5R " ln "2`