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When two moles of ideal gas (Cv = 3/2R) ...

When two moles of ideal gas `(C_v = 3/2R)` heated from 300 K to 600 K at constant volume, calculate `DeltaS_(gas)` :

A

`5R ln 2`

B

`(3)/(2) R ln 2`

C

`3R ln 2`

D

`-3 R ln 2`

Text Solution

Verified by Experts

The correct Answer is:
C

`DeltaS_("gas")=nC_(v,m)ln.(T_(2))/(T_(1))`
`=2xx((5)/(2)-1)Rln2`
`=3Rln2`
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NARENDRA AWASTHI-THERMODYNAMICS-Exercise
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  5. If one mole of an ideal gas Cp = 5/2 R is expanded isothermally at 300...

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