When reaction is at standard state at eq...

When reaction is at standard state at equilibrium, then

`DeltaH^(@)=0`

`DeltaS^(@)=0`

equilibrium constant K=0

equilibrium constant K=1

Text Solution

Verified by Experts

The correct Answer is:

At standard state on equilibrium `DeltaG^(@)=0`
`DeltaG^(@)=0=-RTlnKimpliesK=1`

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