Write bond line formula for propane.

Answer

B

Explanation

`CaCl_(2)(s)+aqrarrCaCl_(2)(aq)+q`
`(CaCl_(2)(aq)+6H_(2)O(l)rarrCaCl_(2).6H_(2)O(s)+23.2)/(CaCl_(2)(s)+6H_(2)OrarrCaCl_(2).6H_(2)O(s)+q+23.2)`
`3.5 = q + 23.2`
`q = - 19.7`
(II) 2 Cl (g) `rarrCl_(2)(g)`
`DeltaH=-ve, DeltaS=-ve`.