Write structure of 3-hydroxybutanoic acid.

Answer

D

Explanation

`Delta_(r)H^(@)=3.Delta_(f)H^(@)(CO,s)+4Delta_(f)H^(@)(CO_(2),g)`
`-Delta_(f)H^(@)(Co_(3)O_(4),s)-4.Delta_(f)H^(@)(CO,g)`
`Delta_(r)H^(@)=-"241 kJ/mol"`
`Delta_(r)S^(@)=3xx30+4xx213.7-102.5-4xx197.7`
= 51.5 J/K-mol
`therefore" "Delta_(r)G^(@)=Delta_(r)H^(@)-T.Delta_(r)S^(@)`
`=-241-(300xx51.5)/(1000)`
`=-256.45"kJ/mol"`