Write bond line formula for ethylene glycol

Answer

C

Explanation

`Delta_(r)H^(@)=Delta_(r)H^(@)(H_(2)O,l)-Delta_(r)H^(@)(OH^(-),aq)=-229`
`-56 =- 285 -Delta_(r)H^(@)(OH^(-),aq),`
`Delta_(r)H^(@)(OH^(-),aq)=-229`
`HF(aq)+OH^(-)(aq)rarrF^(-)(aq)+H_(2)O(l)`
`Delta.H_("neut")^(@)=(-320-285)-(-329-229)`
=-47 kJ/mol