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A high altitude balloon contains 6.81 g ...

A high altitude balloon contains 6.81 g of helium in `1.16xx10^(4)" L at"-23^(@)C.` Assuming ideal gas behaviour, how many grams of helium would have to be added to increase the pressure to `4.0xx10^(-3)` atm?

A

1.27 g

B

1.58 g

C

2.68 g

D

2.23 g

Text Solution

Verified by Experts

The correct Answer is:
d
(d) `P_(1)=(6.81)/(4)xx(0.0821xx250)/(1.1xx104)`
`=3.012xx10^(-3)`
`P_(f)=4xx10^(-3)`
`/_\Puarr=1xx10^(-3)`
`n_("He-added")=(10^(-3)xx1.16xx10^(4))/(0.0821xx250)`
`wt=n_("He")xx4=2.24"gm".`
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